Answer to Question #761 in Calculus for vic
(b) lim_(x→0+)(√(x) (1+sin^2(π/x)));
lim_(x->0) √(x^2+x^4) = 0
the product of 0 and limited function would be equal to zero.
B. The function sin^2(pi/x) is limited in the domain [0,1], so (1+ sin^2(pi/x)) has the values from 1 to 2.
lim_(x->0) √(x) = 0;
the product of 0 and the limited function would be equal to zero
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