# Answer on Calculus Question for allie

Question #5990

an observer 70 meters south of a railroad crossing watches an eastbound train traveling at 60 m per sec. at how many meters per second is the train moving away from the observer 4 sec after it passes through the intersection

Expert's answer

we have right-angled triangle with sides 70 m and 60*4=240 m. the speed is

sqrt(70^2+240^2)/4=62,5 m/sec

sqrt(70^2+240^2)/4=62,5 m/sec

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

Assignment Expert13.04.2012 07:22Dear visitor!

The mistake really took place! Thanks for correcting us

The Doctor12.04.2012 21:2460*4=240, not 280...

## Leave a comment