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Answer to Question #5990 in Calculus for allie
Question #5990
an observer 70 meters south of a railroad crossing watches an eastbound train traveling at 60 m per sec. at how many meters per second is the train moving away from the observer 4 sec after it passes through the intersection
Expert's answer
we have right-angled triangle with sides 70 m and 60*4=240 m. the speed is
sqrt(70^2+240^2)/4=62,5 m/sec
sqrt(70^2+240^2)/4=62,5 m/sec
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Comments
Dear visitor! The mistake really took place! Thanks for correcting us
60*4=240, not 280...
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