Question #5990

an observer 70 meters south of a railroad crossing watches an eastbound train traveling at 60 m per sec. at how many meters per second is the train moving away from the observer 4 sec after it passes through the intersection

Expert's answer

we have right-angled triangle with sides 70 m and 60*4=240 m. the speed is

sqrt(70^2+240^2)/4=62,5 m/sec

sqrt(70^2+240^2)/4=62,5 m/sec

## Comments

Assignment Expert13.04.12, 14:22Dear visitor!

The mistake really took place! Thanks for correcting us

The Doctor13.04.12, 04:2460*4=240, not 280...

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