Question #5532

Mary has a garden in the shape of a sector of a circle; the outer rim of the garden is 25 feet. long and the central angle of the sector is 50 degrees. she wants to add a 3 foot wide walk to the outer rim; how many square feet of paving blocks will she need to build the walk?

Expert's answer

dS - she need to build the

walk.

dS=S1-S2

S1:

2*pi*r=l

(50/360)*2*pi*r=25

r=90/pi

S1=(pi*R^2*50)/360=1125/pi=358 (approximately)

S2:

R=r+3=90/pi +3

S2=(pi*R^2*50)/360=437 (approximately)

S1-S2=78,9 (approximately)

walk.

dS=S1-S2

S1:

2*pi*r=l

(50/360)*2*pi*r=25

r=90/pi

S1=(pi*R^2*50)/360=1125/pi=358 (approximately)

S2:

R=r+3=90/pi +3

S2=(pi*R^2*50)/360=437 (approximately)

S1-S2=78,9 (approximately)

## Comments

Assignment Expert20.10.17, 15:41Dear ttrottewood, please use panel for submitting new questions. Make sure you post the full condition.

ttrottewood20.10.17, 13:32The diagram shows a sector of a circle of radius r cm containing angle Ө radians. The area of the sector is A cm2 and the perimeter of the sector is 50 cm.

a. Find Ө in terms of r

b. Show that A = 25r – r2

Assignment Expert20.02.14, 15:36Dear Real Expert,

Thank you for your remarks. Your are right. We corrected our answer according to your comment.

Real Expert18.02.14, 03:50Bullshit. They are looking for AREA... not ARC LENGTH (if that's indeed what 'Expert' did). Not going to look over such rubbish. REAL answer = 78.93 square feet!

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