Answer to Question #5532 in Calculus for Josh
Question #5532
Mary has a garden in the shape of a sector of a circle; the outer rim of the garden is 25 feet. long and the central angle of the sector is 50 degrees. she wants to add a 3 foot wide walk to the outer rim; how many square feet of paving blocks will she need to build the walk?
Expert's answer
dS - she need to build the
walk.
dS=S1-S2
S1:
2*pi*r=l
(50/360)*2*pi*r=25
r=90/pi
S1=(pi*R^2*50)/360=1125/pi=358 (approximately)
S2:
R=r+3=90/pi +3
S2=(pi*R^2*50)/360=437 (approximately)
S1-S2=78,9 (approximately)
walk.
dS=S1-S2
S1:
2*pi*r=l
(50/360)*2*pi*r=25
r=90/pi
S1=(pi*R^2*50)/360=1125/pi=358 (approximately)
S2:
R=r+3=90/pi +3
S2=(pi*R^2*50)/360=437 (approximately)
S1-S2=78,9 (approximately)
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#181135 on Oct 2017
#181135 on Oct 2017 
Comments
Dear ttrottewood, please use panel for submitting new questions. Make sure you post the full condition.
The diagram shows a sector of a circle of radius r cm containing angle Ө radians. The area of the sector is A cm2 and the perimeter of the sector is 50 cm.
a. Find Ө in terms of r
b. Show that A = 25r – r2
Dear Real Expert,
Thank you for your remarks. Your are right. We corrected our answer according to your comment.
Bullshit. They are looking for AREA... not ARC LENGTH (if that's indeed what 'Expert' did). Not going to look over such rubbish. REAL answer = 78.93 square feet!
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