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# Answer to Question #5416 in Calculus for Samantha

Question #5416
I need to find the double integral... I'll write it as it appears in my book, with the lower limit first

1.) Integral 1,4; Integral 0,y for the function (sqrt(x)) dx dy
2.) Integral -2,2; Integral -2,2 for the function (x+y) dy dx
1.) Integral 1,4; Integral 0,y for the function (sqrt(x)) dx dy

Integral 0,y for (sqrt(x)) =
& = Integral 0,y for (x^0.5) =
& = (x^1.5)/1.5 from x=0 to x=y =
& = (y^1.5)/1.5 - 0 =
& = (y^1.5)/1.5

Integral 1,4 for (y^1.5)/1.5 dy =
& = (y^2.5)/(2.5*1.5) from y=1 to y=4 =
& = (y^2.5)/3.75 from y=1 to y=4 =
& = (4^2.5)/3.75 - (1^2.5)/3.75 =
& = 32/3.75 - 1/3.75 = 31/3.75 = 124/15.

2.) Integral -2,2; Integral -2,2 for the function (x+y) dy dx

Integral -2,2 for (x+y) dy =
& = xy + y&sup2;/2 from y=-2 to y=2 =
& = (2x + 2&sup2;/2) - (-2x + (-2)&sup2;/2) =
& = 2x + 2 + 2x - 2 = 4x

Integral -2,2 for 4x dx =
& = 4x&sup2;/2 from x=-2 to x=2 =
& = 2*2&sup2; - 2*(-2)&sup2; = 8 - 8 = 0.

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