52 814
Assignments Done
98,1%
Successfully Done
In October 2017
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Calculus Question for Liliana Chavez

Question #4842
A box with an open top is to be constructed from a square piece of cardboard, 10 in wide, by cutting out a square from each of the four corners and bending up the sides.
A. What is the length of the side of the square cut out from the corners of the box. Let x = the length of the side of the square cut out of the corners
B. What is the maximum volume of such a box?
Expert's answer
The volume of a box is submitted by function V = S*H, where S is an area of the bottom egde and H is a height of the box. The height H is equal to the length of the side of the square cut out of the corners, so H=x. The length of a side of the bottom egde is l = 10-2x, so S = (10-2x)^2. At last, V(x) = x(10-2x)^2 = 4x^3-40x^2+100x.
Let's find the derivative of volume with respect to x: V' = 12x^2-80x+100. Let's consider equation 12x^2-80x+100 = 0. It has two solutions: x=5, which turns V(x) to zero and x=5/3, which turns V(x) to maximum. So, maximum volume of the box is V(5/3) = 10000/135.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question