Question #4637

Let x = Integral (squ root (sec(t))^4 -1) (dt) from -pi/4 to pi/4

Expert's answer

x=Integral ((squ root (sec(t))^4 -1) (dt)) from -pi/4 to pi/4 = Integral(1/(cos t)^2-1)from -pi/4 to pi/4= tan(t) |_{ -pi/4}^{ pi/4} - pi/4

+pi/4=1+1=2

+pi/4=1+1=2

## Comments

## Leave a comment