# Answer on Calculus Question for michelle

Question #4637

Let x = Integral (squ root (sec(t))^4 -1) (dt) from -pi/4 to pi/4

Expert's answer

x=Integral ((squ root (sec(t))^4 -1) (dt)) from -pi/4 to pi/4 = Integral(1/(cos t)^2-1)from -pi/4 to pi/4= tan(t) |

+pi/4=1+1=2

_{ -pi/4}^{ pi/4}- pi/4+pi/4=1+1=2

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