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Answer to Question #45066 in Calculus for john
Question #45066
In Fourier series, cos npi=(-1)^n, what is cos 2npi?
Expert's answer
If cos(npi)=(-1)^n, substituting n=2m, we come to cos(2mpi)=(-1)^(2m)=1. Thus, cos(2npi)=1.
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