# Answer to Question #43007 in Calculus for shasha

Question #43007

Find a cubic function with the given zeros.

-2, 5, -6

f(x) = x3 + 3x2 + 28x - 60

f(x) = x3 - 3x2 - 28x - 60

f(x) = x3 + 3x2 - 28x - 60

f(x) = x3 + 3x2 - 28x + 60

help me please

-2, 5, -6

f(x) = x3 + 3x2 + 28x - 60

f(x) = x3 - 3x2 - 28x - 60

f(x) = x3 + 3x2 - 28x - 60

f(x) = x3 + 3x2 - 28x + 60

help me please

Expert's answer

If a is a zero of some function then this function divides on (x-a). Of (x-a) is a multiplier of this function. So we get

f(x) = (x+2)(x-5)(x+6) = x

f(x) = (x+2)(x-5)(x+6) = x

^{3} + 3x - 28x - 60.Need a fast expert's response?

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