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Answer to Question #42997 in Calculus for shasha

Question #42997
A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2 + 440t.

After how many seconds does it reach its maximum height?


help me please
Expert's answer
The trajectory of its motion is a parabola with downward branches (the coefficient with t^2 less then 0) 
The maximum height is in the vertex of this parabola. Using the formula t0 = -b/2a we get
tmax = -440/(-2*16) = 13.75 seconds
Answer: 13.75 seconds.

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