# Answer to Question #42997 in Calculus for shasha

Question #42997

A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2 + 440t.

After how many seconds does it reach its maximum height?

help me please

After how many seconds does it reach its maximum height?

help me please

Expert's answer

The trajectory of its motion is a parabola with downward branches (the coefficient with t^2 less then 0)

The maximum height is in the vertex of this parabola. Using the formula t

t

Answer: 13.75 seconds.

The maximum height is in the vertex of this parabola. Using the formula t

_{0 }= -b/2a we gett

_{max }= -440/(-2*16) = 13.75 secondsAnswer: 13.75 seconds.

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