Answer to Question #42990 in Calculus for shasha

Question

Find the zeros of the function.

f(x) = 6x3 + 18x2 + 12x

help me please

Answer 1

We can write the function as f(x)=x(6x^2+18x+12).
From this we can see that one zero is x=0. To find others we need to solve the next quadratic equations x^2+3x+2=0.

The zeros are: x_1=(-3+(9-8)^(1/2))/2=(-3+1)/2=-1 and x_2=(-3-1)/2=-2.

Answer. The zeros are: 0, -1 and -2.