Answer to Question #42990 in Calculus for shasha
f(x) = 6x3 + 18x2 + 12x
help me please
From this we can see that one zero is x=0. To find others we need to solve the next quadratic equations x^2+3x+2=0.
The zeros are: x_1=(-3+(9-8)^(1/2))/2=(-3+1)/2=-1 and x_2=(-3-1)/2=-2.
Answer. The zeros are: 0, -1 and -2.
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