Find an equation for the nth term of the arithmetic sequence.
a14 = -33, a15 = 9
an = -579 + 42(n + 1)
an = -579 + 42(n - 1)
an = -579 - 42(n + 1)
an = -579 - 42(n - 1)
Help me show work and explanation please
1
Expert's answer
2014-05-21T04:43:06-0400
If the initial term of an arithmetic progression is a_1 and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by: a_n=a_1+(n-1)d and in general a_n=a_m+(n-m)d.
So,using the formula above. Let's n=15 and m=14. We obtain a_15=a_14+(15-14)d or 9=-33+d. From this d=-42. a_1=a_n-(n-1)d or a_1=a_15-(15-1)(-42). a_1=-579.
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