# Answer to Question #42278 in Calculus for shasha

Question #42278

Find the range of the function.

f(x) = (x - 2)^2 + 2

f(x) = (x - 2)^2 + 2

Expert's answer

As the function f(x)=(x-2)^2+2 has minimum at the point (2,2), the range of the function is {y in R: y>=2} or y in (2;+infinity).

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