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Answer to Question #3934 in Calculus for pure
Question #3934
Sum the series : -
1- ∑ ( -1/5)^k from ( k = 0 to infinty )
2- ∑ ( 3^k - 5^ k ) / 7^k from ( k=1 to infinity )
3- ∑ ( 1/ k+1 ) from ( k=1 to infinity
1- ∑ ( -1/5)^k from ( k = 0 to infinty )
2- ∑ ( 3^k - 5^ k ) / 7^k from ( k=1 to infinity )
3- ∑ ( 1/ k+1 ) from ( k=1 to infinity
Expert's answer
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#340153 on Dec 2023
#340153 on Dec 2023
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