# Answer to Question #3911 in Calculus for tanmay

Question #3911

FIND DOMAIN of following function:

1) f(x)= 1/x+[x]

2) f(x)=√(sinx-1)

please provide with procedure.

1) f(x)= 1/x+[x]

2) f(x)=√(sinx-1)

please provide with procedure.

Expert's answer

1) x is in denominator, so x≠0 and D = R\{0}.

2) sinx-1 is under the arithmetic square root, so sinx-1 >= 0 ==> sinx >=1 ==> x = π(1+2n) and D = {x = π(1/2+2n), nєZ}.

2) sinx-1 is under the arithmetic square root, so sinx-1 >= 0 ==> sinx >=1 ==> x = π(1+2n) and D = {x = π(1/2+2n), nєZ}.

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