Question #3802

Find the area of the largest isosceles triangle inscribed in a semicircle of radius 10ft., the vertex of the triangle being at the center of the circle.

Expert's answer

The area of isosceles triangle can be found by the following expression:

S = 1/2 a2 sin θ

The largest value of S would be then sin θ = 1, thus θ = 90 degree.

Thus

S = 1/2 10^{2} = 50 ft^{2}.

S = 1/2 a2 sin θ

The largest value of S would be then sin θ = 1, thus θ = 90 degree.

Thus

S = 1/2 10

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