Answer to Question #340774 in Calculus for Jayson

Question #340774

Solve using differentiation rule


y = 2x ^ 2 * sqrt(2 - x)

1
Expert's answer
2022-05-18T09:47:22-0400
"y'=(2x^2\\sqrt{2-x})'=4x\\sqrt{2-x}+\\dfrac{2x^2}{2\\sqrt{2-x}(-1)}"

"=4x\\sqrt{2-x}-\\dfrac{x^2}{\\sqrt{2-x}}"

"=\\dfrac{4x(2-x)-x^2}{2\\sqrt{2-x}}=\\dfrac{8x-5x^2}{2\\sqrt{2-x}}"


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