# Answer to Question #2746 in Calculus for stuff

Question #2746

‎6

^{x-1}=3^{2x}Expert's answer

3

2

2

(2/3)

x-1 =log

x=1+log

^{(x-1)}* 2^{(x-1)}= 3^{2x}2^{(x-1)}= 3^{(2x-x+1)}2

^{(x-1)}= 3^{(x+1)}2

^{(x-1)}= 9*3^{(x-1)}(2/3)

^{(x-1)}= 9x-1 =log

_{(2/3)}9x=1+log

_{(2/3)}9=log_{(2/3)}2/3* 9=log_{(2/3)}6Need a fast expert's response?

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