Question #2746

‎6[sup]x-1[/sup] =3[sup]2x[/sup]

Expert's answer

3^{(x-1)}* 2^{(x-1)} = 3^{2x}2^{(x-1)}= 3^{(2x-x+1)}

2^{(x-1)}= 3^{(x+1)}

2^{(x-1)}= 9*3^{(x-1)}

(2/3)^{(x-1)}= 9

x-1 =log_{(2/3)}9

x=1+log_{(2/3)}9=log_{(2/3)}2/3* 9=log_{(2/3)}6

2

2

(2/3)

x-1 =log

x=1+log

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