# Answer to Question #271 in Calculus for caitlyn

Question #271

What is the area of y=e^x, y=e^6x, x=0, x=ln2?

Expert's answer

1. find the integral - int (e^6x-e^x) from x=0 to ln=2:

it equals to (1/6*e^6x-e^x)|0:ln2 = 1/6(e^6ln2) - e^ln2 -1/6 + 1 = 1/6*2^6 - 2 + 5/6 = 64/6 -7/6 = 57/6

* from x=0 to x=ln2

it equals to (1/6*e^6x-e^x)|0:ln2 = 1/6(e^6ln2) - e^ln2 -1/6 + 1 = 1/6*2^6 - 2 + 5/6 = 64/6 -7/6 = 57/6

* from x=0 to x=ln2

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