# Answer to Question #24657 in Calculus for Lejla

Question #24657

temperature of cup of coffee is given by the following formula (Newton’s

Law of Cooling): T =C+ (T -C)e^kt , where C is the room temperature and T,

the initial temperature of the cup of coffee. Time t is measured in minutes. The

temperature of the coffee when it was served was 1850F. Two minutes later, the

temperature of the coffee dropped to 1550F. When will the temperature of the

coffee drop to 1050F, if the room temperature is 650F

Law of Cooling): T =C+ (T -C)e^kt , where C is the room temperature and T,

the initial temperature of the cup of coffee. Time t is measured in minutes. The

temperature of the coffee when it was served was 1850F. Two minutes later, the

temperature of the coffee dropped to 1550F. When will the temperature of the

coffee drop to 1050F, if the room temperature is 650F

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