# Answer to Question #2081 in Calculus for vinay

Question #2081

if y to the base n = ∫ (sin nx/sin x)dx , then show that y = [2 sin(n-1)x/(n-1)]+y to the base n-2 , hence evaluate ∫ upper limit pi/2,and lower limit 0 (sin7x/sin x)dx.

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