# Answer on Calculus Question for Jess

Question #1989

Find f.

f '' (x) = 3 - 7x - 38x3

f(0) = 1

f '(0) = 4

f(x) = ___________________

f '' (x) = 3 - 7x - 38x3

f(0) = 1

f '(0) = 4

f(x) = ___________________

Expert's answer

Let's integrate f'':

f' = 2x - 7/2 x

Since f'(0) = 4 C

f = x

f(0) =1 , C

f(x) = x

f' = 2x - 7/2 x

^{2 }- 19/2 x^{4}+C_{1}Since f'(0) = 4 C

_{1}= 4f = x

^{2}- 7/6 x^{3}-19/10 x^{5}+4x + C_{2}f(0) =1 , C

_{2}= 1f(x) = x

^{2}- 7/6 x^{3}-19/10 x^{5}+4x + 1.Need a fast expert's response?

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