# Answer to Question #1983 in Calculus for Bindu

Question #1983

Find the most general antiderivative of the function. Use C for any needed constant. (Check your answer by differentiation.) (x>0)

g(x) = (6 - 4 x^3 + 3 x^(7))/x^(7)

G(x)=

g(x) = (6 - 4 x^3 + 3 x^(7))/x^(7)

G(x)=

Expert's answer

g(x) = 6/x

G(x) = int(g(x), dx) = -6/6 x

^{7}- 4x^{3}/x^{7}+ 3x^{7}/x^{7}= 6x^{-7}- 4x^{-4}+ 3G(x) = int(g(x), dx) = -6/6 x

^{-6}+ 4/3 x^{-3}+ 3x + C = - x^{-6}+4/3 x^{-3}+ 3x + CNeed a fast expert's response?

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