Answer to Question #19285 in Calculus for Michael

Question

I'm fed up with this question from my book. I've calculated the constants to this equation but got stuck at the asymptotes and local extreme values calculations which I need to plot the graph, perhaps anyone could help me out or guide me towards the solution of calculating the asymptotes/local extreme values and then to plot the graph.


Equation:


Define the constants A,B,C so that a function which is defined by

f(x) =
(1) (6/pi) arctan(2-(x+2)²) when x < -1
(2) x + c* |x| - 1 when -1 ≥ x ≥ 1
(3) (1/Ax+B) + 4 when x > 1 och Ax + B ≠ 0


is continuous at x = -1 and differentiable in x = 1


_______________


I calculated the constants, A,B,C to:


A = -18


B = 16


C = 7/2


Any help is appreciated,


Thanks, Michael.