Question #1912

Use logarithmic differentiation to find the derivative of the function.
y = x^ln(x)

Expert's answer

x^{lnx} = e ^{ln(x^(ln(x))} = e ^{lnx lnx}

y' = ( e^{lnx lnx} )' = e ^{lnx lnx} *2 lnx * 1/x =2 x^{lnx-1} * lnx

y' = ( e

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