# Answer to Question #1912 in Calculus for Bujju

Question #1912

Use logarithmic differentiation to find the derivative of the function.

y = x^ln(x)

y = x^ln(x)

Expert's answer

x

y' = ( e

^{lnx}= e^{ln(x^(ln(x))}= e^{lnx lnx}y' = ( e

^{lnx lnx})' = e^{lnx lnx}*2 lnx * 1/x =2 x^{lnx-1}* lnxNeed a fast expert's response?

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