Answer to Question #1910 in Calculus for Abhilash
Differentiate the function.
y = 2x log7(√x)
1
2011-03-15T07:35:01-0400
dy/dx = 2 log7(√x) + 2x*1/(2√x) * 1/(√x ln7) = 2 log7(√x)+ 1/ln7
Need a fast expert's response?
Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment