# Answer to Question #1910 in Calculus for Abhilash

Question #1910

Differentiate the function.

y = 2x log7(√x)

y = 2x log7(√x)

Expert's answer

dy/dx = 2 log7(√x) + 2x*1/(2√x) * 1/(√x ln7) = 2 log7(√x)+ 1/ln7

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