Answer on Calculus Question for Abhilash
f(x) = 3x^2 + 2x + 1
f'(c) = (f(b) - f(a))/(b-a) = (f(1) - f(-1))/(1-(-1)) = 4/2 = 2
f'(c) = 6c + 2 = 2
c = 0
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