Let f(x)=1/(3x^(2)+1). Find the open intervals on which f is concave up (down). Then determine the x-coordinates of all inflection points of f.
Use interval notation if you are asked to find an interval or union of intervals. (This link opens instructions below)
f is concave up on the intervals
f is concave down on the intervals
The inflection points occur at x =
find inflection points we must find where f''=0 f'=-6x/(3x^2+1)^2 f''=(6 (-1+9 x^2))/(1+3 x^2)^3 f"=0 9x^2=1 x=1/3 or x=-1/3 inflection points occur at x =1/3 and x=-1/3to define is function concave up or down we must checkf"<0 or f">0 when x<-1/3 then f">0 then f concave down -infinity<x<-1/3-1/3<x<1/3 f"<0 then f concave up x>1/3 f"<0 then f concave down
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