# Answer to Question #17636 in Calculus for nandhini

Question #17636

find the second derivative of x^1/2

Expert's answer

(x^1/2)'=1/2*(x^(-1/2))

(x^1/2)''=(1/2*(x^(-1/2)))'=1/2*(-1/2)*(x^(-3/2))=-1/4*x^(-3/2)

(x^1/2)''=(1/2*(x^(-1/2)))'=1/2*(-1/2)*(x^(-3/2))=-1/4*x^(-3/2)

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