Answer to Question #16187 in Calculus for akansha

Question #16187

the gradient of the curve y-xy+2px+3qy=0 at the point (3,2) is -2/3 the value of p & q are??

Expert's answer

Download Answer

Learn more about our help with Assignments: Calculus Pre-Calculus Differential Calculus Multivariable Calculus

Comments

Assignment Expert

12.10.12, 17:03

You're welcome. We are glad to be helpful. If you really liked our service please press like-button beside answer field. Thank you!

akansha

12.10.12, 15:59

thanx........:)

Assignment Expert

11.10.12, 15:44

First of all, we need to find expression for gradient. Gradient is a vector which components are partial derivatives of the curve. Having curve f(x,y)=y-xy+2px+3qy=0& we can find its gradient as follows: gradx=partial derivative of f by x=-y+2p grady=partial derivative of f by y=1-x+3q So the gradient is grad(x,y)=(-y+2p, 1-x+3q) Then, we're given that at the point (x=3,y=2) gradient equals (-2,3) At first, let's find gradient at the point x=3,y=2. Which is grad(3,2)=(-2+2p, 1-3+3q) Now we equate obtained components to given (-2,3): gradx=-2+2p=-2 grady=1-3+3q=3 From these equations we find p and q Hopefully this will help

akansha

11.10.12, 06:47

sorry will you please ellaborate it, actually i am unable to understand the ans............... i will be thankful to you............ :)

Answer to Question #16187 in Calculus for akansha

Comments

Leave a comment

Related Questions