Answer to Question #15568 in Calculus for hsd
Y(u) = (u^(-2)+u^(-3))*(u^5-1*u^2) = (u+1)/u*(u^3-1)
Y'(u) = (u^3-1)/u-(u+1)(u^3-1)/u^2+3(u+1)u = (3u^4+2u^3+1)/u^2.
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