# Answer on Calculus Question for Taher Ali Habib

Question #10414

If F(x)ăx.x and G(x)ă|x|, then both FoG and GoF are differentiable at xă0 being equal to x.x (or x squared). But G(x) is not differentiable at xă0. Does this contradict the chain rule requirements where both the functions must be differentiable at their respective domain points?

Expert's answer

It doesn't contradict, because the condition in rule is sufficient, so if it's

held the superposition will be differentiable. If it's not held, we can't

definitely say something about the result it may be differentiable or may not,

it depends on certain functions.

held the superposition will be differentiable. If it's not held, we can't

definitely say something about the result it may be differentiable or may not,

it depends on certain functions.

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## Comments

Assignment Expert07.08.2013 10:24You're welcome. We are glad to be helpful.

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Taher Ali Habib30.07.2013 07:15Thank You so much. :) I completely forgot the fact that conditions may either be necessary or sufficient

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