Question #5853

What is an equation of the line that passes through the point (-3,-11) and is parallel to the line whose equation is 2x-y=4?

Expert's answer

Let's find the slope of the first line:

2x - y = 4, or y = 2x - 4, so k = 2.

Now we need to find the line with slope k=2 and passing througt the point (-3,-11):

y = kx+b

Let's substitute the point (-3,-11):

-11 = 2*(-3) + b ==> b = -5

So, y - 2x = -5 is the equation of the required line.

2x - y = 4, or y = 2x - 4, so k = 2.

Now we need to find the line with slope k=2 and passing througt the point (-3,-11):

y = kx+b

Let's substitute the point (-3,-11):

-11 = 2*(-3) + b ==> b = -5

So, y - 2x = -5 is the equation of the required line.

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