# Answer to Question #35765 in Analytic Geometry for Bishnu Parajuli

Question #35765

If c-a=mb then: cot(C-A)/2=(1+mcosC)/ (msinC). How?

Expert's answer

For example :

C = Pi/2

A = 0

m = 2; b=1

cot(Pi/2) = 0, but [1+2*cosPi/2 ] /( 2*Sin[Pi/2] )= 1/2, 1/2 not equal 0

If c-a=mb then: cot(C-A)/2=(1+mcosC)/ (msinC) - false

C = Pi/2

A = 0

m = 2; b=1

cot(Pi/2) = 0, but [1+2*cosPi/2 ] /( 2*Sin[Pi/2] )= 1/2, 1/2 not equal 0

If c-a=mb then: cot(C-A)/2=(1+mcosC)/ (msinC) - false

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