Answer to Question #30158 in Analytic Geometry for jane
Then we can find y from this equality, and write y as linear function of x.
Thus first line is y=(-2/b)x-2/b.
Similarly, with second line we have: second line is y=(-3/2)x+3.5.
If equation of a line is written as y=mx+h, then its slope is coefficient m.
Theorem tells: Lines are perpendicular iff product of their slopes is equal -1.
First slope is m1=-2/b.
Second one is m2=-3/2.
So, they will be perpendicular if (-2/b) * (-3/2) = - 1
Then simplifying we obtain: 3 / b = - 1.
b = -3 - is the answer.
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