Answer on Analytic Geometry Question for Sujata Roy
d) doesn't exist.
If there is third element a, then its complement is such b, that inf(a,b)=0 and
sup(a,b)=1. But as it is chain, then we have a<=b or b<=a. If a<=b then
0=inf(a,b)=a and 1=sup(a,b)=b. Case b<=a is similar.
So there cannot be other third element in C.
|C|=2 or |C|=1 => |C|<=2
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!