Answer to Question #15483 in Analytic Geometry for Sujata Roy
d) doesn't exist.
If there is third element a, then its complement is such b, that inf(a,b)=0 and
sup(a,b)=1. But as it is chain, then we have a<=b or b<=a. If a<=b then
0=inf(a,b)=a and 1=sup(a,b)=b. Case b<=a is similar.
So there cannot be other third element in C.
|C|=2 or |C|=1 => |C|<=2
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