# Answer to Question #922 in Algebra for Michael

Question #922

What is the equation of perpendicalur/paralel to given line through the point (3,2) and given line equation y = 5x-3.

Write down the equation in y = mx=b form.&

Write down the equation in y = mx=b form.&

Expert's answer

Paralel lines have the same slope:

m

for (3,2) : 2 = 5*3 + b; b = -13.

Thus the equation of paralel line is

The slope of perpendicular line equals to negative reciprocal of the slope of given line:

m

for (3,2): 2 = -1/5 * 3 + b; b = 13/5.

The equation of the perpendicular line is

m

_{1}=m_{2}= 5.for (3,2) : 2 = 5*3 + b; b = -13.

Thus the equation of paralel line is

**y = 5x - 13.**The slope of perpendicular line equals to negative reciprocal of the slope of given line:

m

_{2}= -1/5;for (3,2): 2 = -1/5 * 3 + b; b = 13/5.

The equation of the perpendicular line is

**y = -1/5 + 13/5.**Need a fast expert's response?

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