Question #922

What is the equation of perpendicalur/paralel to given line through the point (3,2) and given line equation y = 5x-3.
Write down the equation in y = mx=b form.&

Expert's answer

Paralel lines have the same slope:

m_{1}=m_{2} = 5.

for (3,2) : 2 = 5*3 + b; b = -13.

Thus the equation of paralel line is

** y = 5x - 13. **

The slope of perpendicular line equals to negative reciprocal of the slope of given line:

m_{2} = -1/5;

for (3,2): 2 = -1/5 * 3 + b; b = 13/5.

The equation of the perpendicular line is

** y = -1/5 + 13/5.**

m

for (3,2) : 2 = 5*3 + b; b = -13.

Thus the equation of paralel line is

The slope of perpendicular line equals to negative reciprocal of the slope of given line:

m

for (3,2): 2 = -1/5 * 3 + b; b = 13/5.

The equation of the perpendicular line is

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