What is the equation of perpendicalur/paralel to given line through the point (3,2) and given line equation y = 5x-3.
Write down the equation in y = mx=b form.&
Paralel lines have the same slope: m1=m2 = 5. for (3,2) : 2 = 5*3 + b; b = -13. Thus the equation of paralel line is y = 5x - 13. The slope of perpendicular line equals to negative reciprocal of the slope of given line: m2 = -1/5; for (3,2): 2 = -1/5 * 3 + b; b = 13/5. The equation of the perpendicular line is y = -1/5 + 13/5.