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# Answer to Question #8834 in Algebra for Nick

Question #8834
On the monitor, the graphs of two impulses are recorded on the same screen, where 0&deg;&le;x&le;360&deg;. The impulses are give by the following equations. y=2sin&sup2;x y=1-sinx Find all values x, in degrees, for which the two impulses meet in the interval 0&deg;&le;x&le;360&deg;. [Only an algebraic solution will be accepted.]
1
Expert's answer
2012-04-28T09:42:26-0400
Let&#039;s consider an equation:

2sin&sup2;x = 1-sinx, 0&deg;&le;x&le;360&deg;.

2sin&sup2;x + sinx - 1 = 0 ==&gt; sinx = (-1 &plusmn; 3)/4, so sinx = 1/2 or sinx = -1.

Taking into account that 0&deg;&le;x&le;360&deg;,

sinx = 1/2 ==&gt; x = 30&deg;;
sinx = -1& ==&gt; x = 270&deg;.

So, there are two points of intersection: 30&deg; and 270&deg;.

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