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Question #8444

solve x^2=y+10
3x-y=9

Expert's answer

from second equation y=3x-9

from first

x^2=y+10=3x-9+10=3x+1

x^2-3x+1=0;

x1,2=(3+-sqrt(5))/2;

y1,2=3x(1,2)-9

from first

x^2=y+10=3x-9+10=3x+1

x^2-3x+1=0;

x1,2=(3+-sqrt(5))/2;

y1,2=3x(1,2)-9

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