Answer to Question #81678 in Algebra for Manvir Nahal

Question

A model rocket is launched upward with an initial velocity of 290 feet per second. The height, in feet, of the rocket t seconds after the launch is given by
h = −16t2 + 290t.
How many seconds after the launch will the rocket be 380 feet above the ground? Round to the nearest tenth of a second. (Enter your answers as a comma-separated list.)

Answer 1

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