Answer to Question #7590 in Algebra for jadine
Let the Joseph's weight be J and Tumelos's weight be T. Then J/T = 10/11.
Let the Ceciliaz's weight be C. Then C/M = 6/7.
Also, C = 1.2J.
So, we've got the system of equations:
C/M = 6/7 ==> C = 6M/7.
C = 1.2J ==> J = C/1.2 = 6M/7/1.2 = 5/7 M.
J/T = 10/11 ==> T = 11J/10 = 11/10*5/7 M = 55/70 M.
Finally, we've got:
Mohammed: 1.1 M
Ceciliaz: 6/7 M (≈0.8571 M)
Joseph: 5/7 M (≈0.7143 M)
Tumelos:& 55/70 M (≈0.7857 M)
So, Joseph weighs the least.
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