Question #7311

a number cube is rolled and a quarter is tossed.Find P(even number and heads)

Expert's answer

Assume that the cube and the quarter are fair, that is

for each number 1..6

the probability to get it on the cube is the same

and equal to 1/6, and also

the probability to get either head or tail on

the coin is the same

1/2.

Hence the probability to get an even number on the cube is

P(even number) = P(2) + P(4) + P(6) = 1/6 * 3 = 1/2.

Moreover,

assume that rolling of the cube and tossing of a quarter are

independent,

hence

P(even number and heads) = P(even number) *

P(heads)

= 1/2 * 1/2 = 1/4.

for each number 1..6

the probability to get it on the cube is the same

and equal to 1/6, and also

the probability to get either head or tail on

the coin is the same

1/2.

Hence the probability to get an even number on the cube is

P(even number) = P(2) + P(4) + P(6) = 1/6 * 3 = 1/2.

Moreover,

assume that rolling of the cube and tossing of a quarter are

independent,

hence

P(even number and heads) = P(even number) *

P(heads)

= 1/2 * 1/2 = 1/4.

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