# Answer to Question #6738 in Algebra for bill

Question #6738

the perimeter of a rectangle is 68 cm. the length is 4 cm more than its width. find the dimensions of the rectangle

Expert's answer

Let's denote sides of the rectangle as a-length and b-width.

Then perimeter p=2a+2b=68

Also we know that a=b+4 hence

2a+2b=2(b+4)+2b=68

2b+8+2b=68

4b=60

b=15

and hence a=15+4=19

Then perimeter p=2a+2b=68

Also we know that a=b+4 hence

2a+2b=2(b+4)+2b=68

2b+8+2b=68

4b=60

b=15

and hence a=15+4=19

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