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Answer to Question #659 in Algebra for Francis
Question #659
kq/(x+a)^2-kq/(x-a)^2
Expert's answer
kq/(x+a)^2 - kq/(x-a)^2 =
= (kq * (x-a)^2)/((x+a)^2 * (x-a)^2) - (kq * (x+a)^2)/((x-a)^2 * (x+a)^2) =
= (kq * (x^2-2*x*a+a^2))/((x+a)^2 * (x-a)^2) - (kq * (x^2+2*x*a+a^2))/((x-a)^2 * (x+a)^2) =
= (kq * (x^2-2*x*a+a^2))/((x^2-a^2)^2) - (kq * (x^2+2*x*a+a^2))/((x^2-a^2)^2) =
= kq * (- 4*x*a)/((x^2-a^2)^2)
= (kq * (x-a)^2)/((x+a)^2 * (x-a)^2) - (kq * (x+a)^2)/((x-a)^2 * (x+a)^2) =
= (kq * (x^2-2*x*a+a^2))/((x+a)^2 * (x-a)^2) - (kq * (x^2+2*x*a+a^2))/((x-a)^2 * (x+a)^2) =
= (kq * (x^2-2*x*a+a^2))/((x^2-a^2)^2) - (kq * (x^2+2*x*a+a^2))/((x^2-a^2)^2) =
= kq * (- 4*x*a)/((x^2-a^2)^2)
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