Question #6121

6cos^2x-7cosx+2=0

Expert's answer

let cosx=t so we get an equation 6t^2-7t+2=0 so t=1/2 and t=2/3

then

cos(x)=1/2 or cos(x)=2/3

so x=(+ or -)pi/6 +2pi*k or x=(+ or -)

arccos(2/3)+2pi*k where k is integer

then

cos(x)=1/2 or cos(x)=2/3

so x=(+ or -)pi/6 +2pi*k or x=(+ or -)

arccos(2/3)+2pi*k where k is integer

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