# Answer to Question #5772 in Algebra for Nidhi Fatak

Question #5772

The number 50 is divided into two equal parts, the ratio of the largest part to the smallest is 2/3, then the largest part is?

Expert's answer

First of all, in the question it's said that "number 50 is divided into

Let's denote L one part and m another one. Then

s/L = 2/3

L+s = 50 ==> s = 50-L

(50-L)/L = 2/3

50/L - 1 = 2/3

50/L = 5/3

L/10 = 3

L = 30

s = 50-30 = 20.

So, the large part is 30 and the small part is 20.

__" and though "ratio of the__**two equal parts**__largest part__to the__smallest__is 2/3". obviously, two equal parts are equal hence they are 25,25. If we drop it off and consider the second part saying about ratio then we will act in the following way. Let's take a look.Let's denote L one part and m another one. Then

s/L = 2/3

L+s = 50 ==> s = 50-L

(50-L)/L = 2/3

50/L - 1 = 2/3

50/L = 5/3

L/10 = 3

L = 30

s = 50-30 = 20.

So, the large part is 30 and the small part is 20.

## Comments

John Latham25.12.11, 00:36If the parts are equal, there is no larger part.

John Latham25.12.11, 00:35If the number 50 is divided into 2 equal parts, each part would be 25 and there would be no larger or smaller part.

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