# Answer on Algebra Question for Erica

Question #5253

prove that for n there exists a natural number, (2n/n)+(2n/n+1)=1/2((2n+2)/(n+1))

Expert's answer

n<>0

n<>-1

2(2n(n+1)+2n(n+1)+n(n+1))/(n(n+1))-2n(n+1)/(n(n+1))=0

8n(n+1)/(n(n+1)=0

8=0

4=-4

for n, there exists a positive integer

n<>-1

2(2n(n+1)+2n(n+1)+n(n+1))/(n(n+1))-2n(n+1)/(n(n+1))=0

8n(n+1)/(n(n+1)=0

8=0

4=-4

for n, there exists a positive integer

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