# Answer to Question #4413 in Algebra for zm

Question #4413

make y the subject.

x=2/3y^2+4

x=2/3y^2+4

Expert's answer

Let's subtract 4 from each part of equation:

x-4 = 2/3y^2

Trransfering the multiplier:

3/2(x-4) = y^2

So, y = (3/2(x-4))^0.5

x-4 = 2/3y^2

Trransfering the multiplier:

3/2(x-4) = y^2

So, y = (3/2(x-4))^0.5

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