Answer to Question #43856 in Algebra for Jeremy
x^2-4x+13=(x-2)^2+9. So, the zeros of the equation x^2-4x+13: 2-3i, 2+3i.
Thus, we have that 1, 2-3i and 2+3i are zeros of the equation -x^3+5x^2-17x+13=0.
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