# Answer on Algebra Question for Zachary

Question #41814

what is the center of a circle with the following equation? (x-1)^2+(y+2)^2=49

Expert's answer

Center of a circle is (x

_{0};y_{0})=(1;-2), because a circle with the equation (x-x_{0})^{2}+(y-y_{0})^{2}=R^{2 }has coordinates (x_{0};y_{0}).Need a fast expert's response?

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