Answer to Question #41814 in Algebra for Zachary

Question #41814
what is the center of a circle with the following equation? (x-1)^2+(y+2)^2=49
1
Expert's answer
2014-04-28T13:38:26-0400
Center of a circle is (x0;y0)=(1;-2), because a circle with the equation (x-x0)2+(y-y0)2=R2 has coordinates (x0;y0).

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