# Answer to Question #390 in Algebra for Zena

Question #390

Mike, Mark, and Melvin painted a fence. Mike painted the first 1/3 of the fence. Mark painted 3/5 of what remained. Melvin painted the final 40ft. How long is the fence?

Expert's answer

Let the length of the fence is x, so Mike painted (x/3), Mark painted ((x-x/3)*3/5) and Melvin painted 40. We can write the equation:

(х/3)+((х-(х/3))*3/5)+40 = х

(х/3)+(2х/5)+40 = х

х-(х/3)-(2х/5) = 40

4х/15 = 40

х = 150

So, the length of the fence is 150 ft.

(х/3)+((х-(х/3))*3/5)+40 = х

(х/3)+(2х/5)+40 = х

х-(х/3)-(2х/5) = 40

4х/15 = 40

х = 150

So, the length of the fence is 150 ft.

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